Re: Stoichiometry help please?

.../32 ~ 0.06 mole. Since this is less than the ammonia and you need 5/4 mole of oxygen per mole of ammonia, you know oxygen is the limiting reagent. The amount of unreacted ammonia n_unreacted(NH3) = 0.1 - 0.06 * 4/5 = 0.052 mole or m_unreacted(NH3) = 0.052 * 17 ~ 0.88 g. For every mole of oxygen yo...